If a wire is stretched to double of its length.What will be the strain

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The discussion centers on calculating the strain of a wire when it is stretched to double its original length. The correct formula for strain is defined as the change in length divided by the original length. When the wire's initial length is denoted as 'l', the final length becomes '2l', resulting in a change in length of 'l'. Therefore, the strain is calculated as 'l/l', which equals 1, confirming that the strain of the wire is indeed 1.

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If a wire is stretched to double of its length.What will be the strain of wire?I need to prove it mathematically that how it becomes 1.
 
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What is the basic definition of strain?
Look it up and put the values for initial and final length in the formula.
 


Thanks you sir.
Basic definition is:Change in length/original length.So change in length is 2l.And original length is l.So it becomes 2.While the correct answer to this statement is 1.
 


You've got something messed up here.

The CHANGE in length. So, what is the final length? 2I. What's the initial? I.
CHANGE = FINAL LENGTH - INITIAL LENGTH
2I is not the change. Keep that in mind and try the equation again. See what you get.
 


Thanks you very much!Got it.
 

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