- #1

mathdad

- 1,288

- 0

My Work:

Let x = time when both pipes are used together

(1/5) + (1/3) = 1/x

I found x to be 15/8 hours.

Must I now multiply (15/8)(2/3)?

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- MHB
- Thread starter mathdad
- Start date

- #1

mathdad

- 1,288

- 0

My Work:

Let x = time when both pipes are used together

(1/5) + (1/3) = 1/x

I found x to be 15/8 hours.

Must I now multiply (15/8)(2/3)?

- #2

Wilmer

- 307

- 0

Correct.I found x to be 15/8 hours.

Must I now multiply (15/8)(2/3)?

Yes.

- #3

mathdad

- 1,288

- 0

Correct.

Yes.

It took several tries before I found the correct set up. Unfortunately, no such thing as ENOUGH TIME when taking a test.

- #4

HOI

- 923

- 2

That's why you "practice, practice, practice" **before** the test!

- #5

mathdad

- 1,288

- 0

That's why you "practice, practice, practice"beforethe test!

My classroom days ended in December 1993.

- #6

HOI

- 923

- 2

Then what "test" were you talking about?

- #7

Wilmer

- 307

- 0

Test tickle?

- #8

MarkFL

Gold Member

MHB

- 13,302

- 11

\(\displaystyle t=\frac{2}{3}\cdot\frac{15}{8}\text{ hr}=\frac{5}{4}\text{ hr}\)

- #9

mathdad

- 1,288

- 0

Correct.

Yes.

(15/8)(2/3) = 5/4 hrs

- #10

Wilmer

- 307

- 0

Stick a pink star on your forehead :)

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