If cosθ = -5/13 and 0 <= θ <= 2π, what are possible values of θ?

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SUMMARY

The problem involves finding the values of θ where cosθ = -5/13 within the interval 0 ≤ θ ≤ 2π. The correct solutions are θ = 1.96 radians in the second quadrant and θ = 4.32 radians in the third quadrant. The discussion clarifies that the book's answer of 5.14 radians is incorrect, as it mistakenly includes an angle from the fourth quadrant instead of confirming the values derived from the second and third quadrants.

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Homework Statement



If cosθ = -5/13 and 0 <= θ <= 2π, what are possible values of θ?

Homework Equations



The Attempt at a Solution


θ is in quadrant 2 or 3

in quadrant 2:
related acute = cos^{-1}(5/13)
= 1.18
θ = π - 1.18
= 1.96 radians

in quadrant 3:
related acute angle = 1.18
θ = π + 1.18
= 4.32 radians

Those are the two values I got for θ. But my book says the answer is 5.14. Can you tell me where I am going wrong?
 
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Where didn't you go wrong?

Nah, I'm just kidding :biggrin: The book's answer is wrong, you're right. They accidentally included the angle in the 4th quadrant rather than the 3rd as you've correctly done.
 

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