If light travels for 3.0ns in ethyl alcohol, how much furthe

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The discussion revolves around calculating the distance light travels in ethyl alcohol compared to benzene over a time of 3.0 ns. The index of refraction for ethyl alcohol is 1.36 and for benzene is 1.50, leading to a calculated ratio of 1.10 for the speed of light in ethyl alcohol relative to benzene. Participants emphasize the importance of correctly applying the ratio to find the difference in distances traveled in both substances during the same time interval. Clarifications are made regarding the need to express calculations with proper units and to visualize the problem for better understanding. Ultimately, the key focus is on determining how much further light travels in ethyl alcohol than in benzene within the specified time.
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Ratio is 1.10 for part 1.
1. Determine the ratio for the speed of light in ethyl alcohol (n=1.36) to the speed of light in benzene (n=1.50).

2. If light travels for 3.0ns in ethyl alcohol, how much further will it travel in this material than it would in benzene? answer will be in terms of speed of light in benzene, Vbenzene.

here is my work for part 2 but i don't think its right,

for part 2 knowing Ve/Vb = 1.10

d=Vet

Vc=(1.10)Vb
d=Vet
Ve=(1.10)Vb
de=(1.1)Vbt
de=(3.0x10^9s)Vb

d=1.10Vb x 3.0x10^-3

d=1.10 x 3x10^-3 Vb

Vb(3x10^-9) = d
 
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tangowhiskey said:
Ratio is 1.10 for part 1.
1. Determine the ratio for the speed of light in ethyl alcohol (n=1.36) to the speed of light in benzene (n=1.50).

2. If light travels for 3.0ns in ethyl alcohol, how much further will it travel in this material than it would in benzene? answer will be in terms of speed of light in benzene, Vbenzene.

here is my work for part 2 but i don't think its right,

for part 2 knowing Ve/Vb = 1.10

d=Vet

Vc=(1.10)Vb
d=Vet
Ve=(1.10)Vb
de=(1.1)Vbt
de=(3.0x10^9s)Vb

d=1.10Vb x 3.0x10^-3

d=1.10 x 3x10^-3 Vb

Vb(3x10^-9) = d
Your final result doesn't make any sense. All you've done is multiply Vb by 3 ns. The question asks how much further does light travel in ethyl alcohol in 3 ns than it does in the same time in benzene.

What's the definition of the index of refraction n of a material, in terms of the speed of light c?

https://en.wikipedia.org/wiki/Refractive_index
 
SteamKing said:
Your final result doesn't make any sense. All you've done is multiply Vb by 3 ns. The question asks how much further does light travel in ethyl alcohol in 3 ns than it does in the same time in benzene.

What's the definition of the index of refraction n of a material, in terms of the speed of light c?

https://en.wikipedia.org/wiki/Refractive_index
correct me if I am wrong but it might be

speed of light in benzene (3x10^8)/(1.50) = 2x10^8 m/s

now I am unclear about what to do..
 
tangowhiskey said:
correct me if I am wrong but it might be

speed of light in benzene (3x10^8)/(1.50) = 2x10^8 m/s

now I am unclear about what to do..
Well, you know (I hope) that distance traveled = speed × time.

In step 1, you calculated the ratio of the indices of refraction for ethyl alcohol to benzene and found that ratio to be about 1.10. This is how much faster light travels thru ethyl alcohol than benzene. Over 3 ns, how much farther does light travel thru ethyl alcohol than benzene? "How much farther" means what's the difference in distance traveled in the two liquids during the same amount of time.
 
SteamKing said:
Well, you know (I hope) that distance traveled = speed × time.

In step 1, you calculated the ratio of the indices of refraction for ethyl alcohol to benzene and found that ratio to be about 1.10. This is how much faster light travels thru ethyl alcohol than benzene. Over 3 ns, how much farther does light travel thru ethyl alcohol than benzene? "How much farther" means what's the difference in distance traveled in the two liquids during the same amount of time.

so then

d = (1.10)(3x10^-9) = 3.3 x 10^-9 seconds

??
 
tangowhiskey said:
so then

d = (1.10)(3x10^-9) = 3.3 x 10^-9

??
No, you're not even writing out the units with your calculations, which you should always do. Remember, 1.10 is a ratio; it is unitless. If you multiply a ratio by a velocity, you're going to get another velocity, not a distance.

In this case, perhaps making a simple sketch would help you visualize what's happening.

Pretend you have two containers, one filled with ethyl alcohol and the other filled with benzene. How would you show the distance light travels thru each container in 3 ns? How would you show the difference in the distance light traveled in each fluid?
 
SteamKing said:
No, you're not even writing out the units with your calculations, which you should always do. Remember, 1.10 is a ratio; it is unitless. If you multiply a ratio by a velocity, you're going to get another velocity, not a distance.

In this case, perhaps making a simple sketch would help you visualize what's happening.

Pretend you have two containers, one filled with ethyl alcohol and the other filled with benzene. How would you show the distance light travels thru each container in 3 ns? How would you show the difference in the distance light traveled in each fluid?

my physics is too poor to figure this out
 
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