If the atmospheric pressure is 0.975 atm

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priscilla89
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Homework Statement



If the atmospheric pressure is 0.975 atm, what is the pressure of the enclosed gas when its an open-tube manometer and the h is 52 cm?

The Attempt at a Solution



I know you would have to set up a proportion. I was thinking

.975 / 1 = x / 760

x = 741 torr

But you will need the density of this gas, right?
 
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priscilla89 said:

Homework Statement



If the atmospheric pressure is 0.975 atm, what is the pressure of the enclosed gas when its an open-tube manometer and the h is 52 cm?

The Attempt at a Solution



I know you would have to set up a proportion. I was thinking

.975 / 1 = x / 760

x = 741 torr

But you will need the density of this gas, right? I know we'll have to use the height but I don't know how.

This question is at this website below, its on pg 399 Q 15 i. I will appreciate the help for just one question at least.

http://www.chemistry.ohio-state.edu/~rzellmer/chem122/homewk/homewk9/122ch10_exer9.pdf"
 
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