The discussion centers on calculating the pressure of an enclosed gas using an open-tube manometer when the atmospheric pressure is 0.975 atm and the height difference (h) is 52 cm. The solution involves setting up a proportion based on the relationship between atmospheric pressure and the pressure in torr. The calculated pressure of the gas is 741 torr. Additionally, the density of the gas may be necessary for further calculations, although it is not explicitly required for this specific problem.
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priscilla89 said:Homework Statement
If the atmospheric pressure is 0.975 atm, what is the pressure of the enclosed gas when its an open-tube manometer and the h is 52 cm?
The Attempt at a Solution
I know you would have to set up a proportion. I was thinking
.975 / 1 = x / 760
x = 741 torr
But you will need the density of this gas, right? I know we'll have to use the height but I don't know how.