- #1

Jaco Viljoen

- 160

- 9

## Homework Statement

If log

_{3}(x-3)-log

_{1/3}(x+1) is expressed in terms of a logarithm with base 9, then it is equal to?

## Homework Equations

log

_{b}a=log

_{c}a/log

_{c}b

## The Attempt at a Solution

I know I need to get rid of the 1/2 by multiplying but can't remember how to apply it.

log

_{3}(x-3)-log

_{1/3}

=log

_{9}(x-3) / log

_{9}3 - log

_{9}(x+1) / log

_{9}1 / 3

= log

_{9}(x-3) / 1/2 - log

_{9}(x+1) / -1/2

Can someone tell me how to display fractions correctly?

Thank you.

Jaco

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