Image formation with a convex mirror

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SUMMARY

The discussion focuses on image formation using a convex mirror, specifically involving an object height of 2.00 cm placed 12.0 cm in front of a mirror with a radius of curvature of 8.00 cm. The key equations utilized are the mirror equation \(1/p + 1/q = 1/f\) and the focal length calculation \(f = (1/2)R\). The participant successfully deduces the image location by calculating the focal length and applying the mirror equation.

PREREQUISITES
  • Understanding of convex mirrors and their properties
  • Familiarity with the mirror equation
  • Knowledge of focal length calculation
  • Basic skills in ray diagram drawing
NEXT STEPS
  • Study the derivation and applications of the mirror equation
  • Learn how to draw ray diagrams for different types of mirrors
  • Explore the characteristics of images formed by convex mirrors
  • Investigate the significance of magnification in mirror optics
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of image formation with convex mirrors.

monke
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Homework Statement



An object 2.00cm high is placed 12.0cm in front of a convex mirror with radius of curvature of 8.00cm.

Homework Equations



Where is the image formed? Draw a ray diagram

The Attempt at a Solution



do i use the equation m=-q/p? if so then (object distance)p= 12cm. how do i find q using the information given?

Thank you
 
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actually i may have gotten it. if i find f using f=(1/2)R the pulg into the mirror equation
1/p+ 1/q = 1/f and solve i have the answer?
 

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