Focal length of a convex mirror

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Homework Help Overview

The discussion revolves around determining the focal length of a convex mirror based on the relationship between object distance and image distance when the mirror is replaced with a flat mirror. The original poster presents a scenario where an object is placed 12.0 cm in front of a convex mirror, and the image distance changes when a flat mirror is used.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between object distance and image distance for both convex and flat mirrors. There are attempts to apply the mirror formula and questions about the nature of the images produced by the mirrors.

Discussion Status

Participants are actively discussing the implications of the image distances for both types of mirrors. Some have provided calculations for the image distances and are questioning the signs associated with these distances, particularly in the context of virtual versus real images.

Contextual Notes

There is an ongoing exploration of the assumptions regarding the distances and the nature of the images produced by the mirrors. The discussion highlights the need for clarity on the definitions and signs used in the mirror equations.

aChordate
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Homework Statement



An object is 12.0 cm in front of a convex mirror. When the convex mirror is replaced
with a flat mirror, the image distance is 5.0 cm farther away from the mirror. What is the
focal length of the convex mirror?

Homework Equations



f=-1/2R

1/do+1/di=1/f

The Attempt at a Solution



(1/0.12m)+1/di=1/f
?

12+5cm=17cm=0.17m

(1/0.17m)+1/di=1/f
?
 
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aChordate said:

Homework Statement



An object is 12.0 cm in front of a convex mirror. When the convex mirror is replaced
with a flat mirror, the image distance is 5.0 cm farther away from the mirror. What is the
focal length of the convex mirror?

Homework Equations



f=-1/2R

1/do+1/di=1/f

The Attempt at a Solution



(1/0.12m)+1/di=1/f
?

12+5cm=17cm=0.17m

(1/0.17m)+1/di=1/f
?

How is the image distance related to the object distance in case of a flat mirror?


ehild
 
ehild said:
How is the image distance related to the object distance in case of a flat mirror?


ehild

They would be equidistant to the mirror?
 
Yes. So the mirror image in case of flat mirror is farther away by 5 cm than the image produced by the convex mirror. If the object distance is 12 cm and the image distance is shorter by 5 cm, what can be di?

ehild
 
di=12cm for the flat mirror
di=7cm for the convex mirror?
 
Using the above di, I got f=0.12m.
 
The image is behind the mirror.
 
aChordate said:
di=12cm for the flat mirror
di=7cm for the convex mirror?
The image is at 7 cm distance from the mirror, but the mirror is convex, is the image virtual or real?
What is the sign of di ? ehild
 
aChordate said:

Homework Statement



An object is 12.0 cm in front of a convex mirror. When the convex mirror is replaced
with a flat mirror, the image distance is 5.0 cm farther away from the mirror. What is the
focal length of the convex mirror?

Homework Equations



f=-1/2R

1/do+1/di=1/f

The Attempt at a Solution



(1/0.12m)+1/di=1/f
?

12+5cm=17cm=0.17m

(1/0.17m)+1/di=1/f
?

Have you solved the problem? A quick ray Trace will do it for you.
 
  • #10
The problem statement tells us that the image is behind the mirror.
 

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