Impulse from basket ball against ground at an angle

In summary, the basketball player bounces a 0.60-kg basketball off the court with a speed of 6.5 m/s at an angle of 50° from the vertical. The ball rebounds with the same speed and angle, resulting in a change in the y velocity of -2v. Using the formula for impulse as the product of force and change in time, we can find the impulse delivered to the ball by the court by calculating the change in momentum.
  • #1
okscuba45
2
0

Homework Statement



To basketball player bounces the 0.60-kg basketball to another player by bouncing it off the court. The ball hits the court with a speed of 6.5 m/s at an angle of 50° from the vertical. If the ball rebounds with the same speed and angle, what was the impulse delivered to it by the court?


Homework Equations



I know that Impulse is the change in momentum, or the force times the change in time.

The Attempt at a Solution



I cannot figure out how to find the Impulse with simply the velocity an angles. Is there a change in momentum if all it does is change direction? If so, how do I use the angles to calculate the change?
I try doing the x/y components of the velocity but it seems to cancel out.
 
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  • #2
You must use xy components. There is no change in the x velocity, so no impulse. But there is a change in the y velocity - it reverses direction so you'll have something like Δv = -v - v = -2v. Of course you know the number for v, the vertical component of the 6.5 m/s.
 
  • #3


I would approach this problem by breaking it down into its fundamental principles. First, we know that impulse is equal to the change in momentum. In this case, the basketball is bouncing off the court, so we can assume that the momentum before and after the bounce is equal in magnitude but opposite in direction. This means that the change in momentum is equal to twice the initial momentum.

To calculate the initial momentum, we need to use the given information about the ball's mass and initial velocity. We can use the equation p = mv, where p is momentum, m is mass, and v is velocity.

Next, we need to consider the angle at which the ball hits the court. Since the ball is bouncing off at the same angle, we can assume that the change in direction is due to a change in the vertical component of the velocity. This means that the horizontal component of the velocity remains the same before and after the bounce.

Using basic trigonometry, we can find the horizontal and vertical components of the initial velocity. The horizontal component is equal to 6.5 m/s * cos(50°) and the vertical component is equal to 6.5 m/s * sin(50°).

Now, we can use these components to calculate the initial momentum in the x and y directions. The x-direction momentum is equal to the mass of the ball (0.60 kg) multiplied by the horizontal component of the velocity. The y-direction momentum is equal to the mass of the ball multiplied by the vertical component of the velocity.

Finally, we can calculate the total initial momentum by adding the x and y components together. This will give us the magnitude of the initial momentum, which we can then double to find the change in momentum.

Therefore, the impulse delivered to the ball by the court is equal to twice the initial momentum, which we have calculated using the given information about the ball's mass and initial velocity.
 

What is impulse in basketball?

Impulse in basketball refers to the change in momentum of a basketball when it makes contact with the ground at a certain angle.

How does the angle of impact affect the impulse of a basketball?

The angle of impact plays a significant role in determining the magnitude and direction of the impulse on a basketball. A steeper angle of impact will result in a greater change in momentum and therefore a larger impulse.

What factors influence the impulse of a basketball when it hits the ground at an angle?

The impulse of a basketball when it hits the ground at an angle is influenced by the velocity of the ball, the mass of the ball, the angle of impact, and the elasticity of the ground and ball materials.

How can the impulse of a basketball be calculated?

The impulse of a basketball can be calculated using the formula: Impulse = Change in momentum = Mass x Change in velocity. This formula takes into account the mass and velocity of the ball before and after it makes contact with the ground.

What is the practical application of understanding impulse in basketball?

Understanding impulse in basketball can help players improve their shooting and passing skills, as well as help coaches develop effective training strategies. It can also be applied in the design of basketball equipment, such as shoes and balls, to optimize performance.

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