Impulse in an inelastic collision

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SUMMARY

The discussion focuses on calculating the impulse experienced by two particles during an inelastic collision. Particle 1, with a mass of 10 kg, and Particle 2, with a mass of 30 kg, both travel towards each other at 10 m/s. The correct final velocity after the collision is determined using the formula for inelastic collisions, which is (m1u1 + m2u2) / (m1 + m2). The impulse for each particle is calculated using the formula I = Ft = mv - mu, where the initial and final velocities must be accurately determined to find the impulse values.

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  • Knowledge of impulse-momentum theorem
  • Basic algebra for solving equations
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Students studying physics, particularly those focusing on mechanics and collisions, as well as educators looking for examples of inelastic collision problems.

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Homework Statement


2 particles travel towards each other at 10ms-1. Particle 1 has a mass of 10kg and particle 2 has a mass of 30kg. It is an inelastic collision.

Find the magnitude of the Impulse of particle 1 and 2.


Homework Equations


I=Ft=mv-mu
m1u1+m2u2=(m1+m2)V

The Attempt at a Solution


I'm able to calculate the final velocity of the two particles after the collision when they have joined.
((10×10)+(30×10))/(10+30)=10ms-1
but I cannot now calculate the impulse of any of the particles.
For example for particle 1:
mv-mu=(10×10)-(10×10)=0

Could anyone help?
 
Physics news on Phys.org
10m/s is not the final velocity. Keep in mind that they are colliding, their motion is not in the same direction.

Oh, and please don't forget units.
 

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