Impulse Matching: Finding the Unit Impulse Response

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Finding the unit impulse response of a system involves assuming x(t) = δ(t) with zero initial conditions at t=0^-. The impulse response h(t) includes the system's modes for t ≥ 0^+, leading to the expression h(t) = A δ(t) + modes for t ≥ 0. This formulation accounts for the system's immediate response to the impulse at t=0, represented by a scalar multiple of the Dirac delta function. For t > 0+, the response reflects the system's characteristic oscillations without the delta function itself. Understanding this distinction is crucial for analyzing system behavior following an impulse.
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Impulse Matching

In regards to finding the unit impulse response of a system. We assume that x(t) = \delta (t) and that the intials conditions at t=0^_ are all zero. The impulse response h(t) therefore must consists of the systems's modes for when t \geq 0^+. But why is it that h(t) = A \delta(t) + \text{modes} for t \geq 0?
 
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I guess the simplest explanation would be that if the domain of the response is extended to include t = 0 (or 0-) it will have an additional component: the system's response to the impulse while the impulse is being applied, which is of course a scalar multiple of the Dirac delta function.
Since the delta function is non-zero for t = 0- and 0 but not for 0+, the response for t >= 0+ will not involve the delta function at all, just it's residual effect (the system's characteristic oscillations). You will generally only be concerned with the response for t > 0+.
That's what I think it is, but I might be wrong. I appologise for the lack of mathematical rigour in this post.
 
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