Impulse of a ball being thrown on to the wall

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SUMMARY

The impulse experienced by a tennis ball of mass 0.075 kg thrown at a wall with a speed of 15 m/s at a 45˚ angle can be calculated using the formula for impulse, which is the change in momentum. When the ball strikes the wall and rebounds at the same speed and angle, the impulse is equal to the change in velocity, which is a vector quantity. The direction of the velocity changes upon rebounding, resulting in a net impulse that can be quantified by considering the initial and final velocity vectors.

PREREQUISITES
  • Understanding of impulse and momentum concepts
  • Knowledge of vector addition and subtraction
  • Familiarity with basic physics equations related to motion
  • Ability to analyze motion at angles
NEXT STEPS
  • Study the concept of impulse in physics
  • Learn about vector components and how to resolve them
  • Explore momentum conservation in elastic collisions
  • Review examples of impulse calculations in real-world scenarios
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of impulse and momentum in action.

blee2x2
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Homework Statement


a tennis ball of mass m = 0.075kg is thrown at a wall with a speed of v = 15m/s. It strikes the wall at a 45˚ angle and rebounds with the same speed at 45˚. What is the impulse given by the wall?

Homework Equations


impulse = Change in mass x Change in velocity

The Attempt at a Solution


Since the velocity is not changing once the ball rebounds from the wall the impulse is the same as it is when it strikes the wall?
 
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blee2x2 said:
Since the velocity is not changing once the ball rebounds from the wall the impulse is the same as it is when it strikes the wall?
Velocity is a vector; it has direction. The speed does not change from the bounce, but the velocity does.
Do you know how to add and subtract vectors?
 

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