Impulse of a Ball - Greatest Change in Momentum

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SUMMARY

The discussion centers on the impulse experienced by a tennis ball during three distinct phases: throwing, bouncing, and catching. It is established that the bounce results in the greatest change in momentum, calculated as -2m\vec{v}, compared to the throw and catch phases, which yield changes of m\vec{v} and -m\vec{v}, respectively. The reasoning is based on the principle that the momentum before and after the bounce involves a reversal of velocity, leading to a significant change. The analysis assumes no loss of kinetic energy, affirming that the conclusion remains valid even if energy is lost.

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Homework Statement



If a tennis player were to throw his ball against a wall, which impulse would be the greatest? The throw, the bounce, or the catch?

Homework Equations



I = F * t
P = m * v

The Attempt at a Solution



I believe the bounce is the greatest, as it has the greatest change in momentum, but I can't explain my thought...
 
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yes you are right. bounce has the greatest change in momentum. let's say that velocity before the impact is \vec{v} , then velocity after the bounce would be
-\vec{v}. so initial momentum is m\vec{v} and final momentum is
-m\vec{v}. so the change in momentum would be -m\vec{v}-m\vec{v} which is -2m\vec{v}. but when the ball is caught, final momentum is zero, so the change in momentum is 0-m\vec{v} which is -m\vec{v}
same argument can be made for the case when the the ball is thrown.

Edit: I am assuming above that the kinetic energy is not lost. Even if the kinetic energy is lost, the reasoning is not affected.
 
IssacNewton said:
yes you are right. bounce has the greatest change in momentum. let's say that velocity before the impact is \vec{v} , then velocity after the bounce would be
-\vec{v}. so initial momentum is m\vec{v} and final momentum is
-m\vec{v}. so the change in momentum would be -m\vec{v}-m\vec{v} which is -2m\vec{v}. but when the ball is caught, final momentum is zero, so the change in momentum is 0-m\vec{v} which is -m\vec{v}
same argument can be made for the case when the the ball is thrown.

Edit: I am assuming above that the kinetic energy is not lost. Even if the kinetic energy is lost, the reasoning is not affected.

Hey! Thanks for the reply! It makes sense, and I assume when the ball is thrown it is the reverse? The initial momentum is zero?

Thank you!
 
yes, when the ball is thrown, the initial momentum is zero. and final momentum is
m\vec{v} so the change in momentum is m\vec{v} which is a smaller change in absolute terms than in the case of bouncing ball.
 

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