jbriggs444
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As is, it is an analysis of an idealized impact of a perfectly elastic hammer with an unyielding surface. One could re-do the analysis to determine the energy absorbed from a hammer before the nail starts to budge. It'll likely be messier.Delta2 said:ok @jbriggs444 thanks for the analysis. But i don't understand what is the energy E? Is it the kinetic energy of the hammer before the collision? Or just the portion of kinetic energy that goes as energy required to deform the hammer?
So we have a hammer with energy E and stiffness k. And we have a target that resists our impact, remaining immobile until subject to force F.
We begin by determining how far the hammer deforms when the target it just ready to budge.$$s=F/k$$The energy absorbed into deformation of the hammer is given by $$E_d=\frac{1}{2}ks^2 = \frac{1}{2}k(F/k)^2 = \frac{1}{2}F/k$$The massless nail and deformed hammer now advance together into the work against resisting force F until they decelerate to a stop. The deformation energy in the hammer is then released as the hammer rebounds.
One can see that the energy lost to deformation in the hammer is inversely proportional to k in this case. Stiffer is better. However, it is also directly proportional to F. For a very loosely fitting nail, the loss may be negligible. For a tight fitting nail it may exceed 100% and the nail may remain stubbornly in place.
That is a disagreement that I want to tip-toe quietly past.Delta2 said:Which explanation is primary or better in your opinion?