In a paper says that the limit when [tex]\alpha \to 0[/tex] with [tex]

  • #1

Main Question or Discussion Point

In a paper says that the limit when [tex]\alpha \to 0[/tex] with [tex] \sigma = \pm 1 [/tex] of:

[tex]\frac{1}{4 \alpha}(1 + \sigma \sqrt{1 - \frac{8}{l^2} \alpha } )[/tex]

has a well defined limit only when [tex] \sigma = - 1 [/tex],

¿why???????...I don't understand
 

Answers and Replies

  • #2
disregardthat
Science Advisor
1,854
33


Well, calculate the limit for sigma = -1, and see what happens when sigma = 1 (try to calculate it).
 

Related Threads for: In a paper says that the limit when [tex]\alpha \to 0[/tex] with [tex]

Replies
2
Views
1K
  • Last Post
Replies
3
Views
4K
Replies
4
Views
3K
Replies
5
Views
1K
Replies
11
Views
2K
Replies
3
Views
1K
Top