In ground state, are spins aligned or anti-aligned?

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SUMMARY

The ground state energy of two ions with spin is determined by their alignment, which is influenced by the Hamiltonian expression. For a Hamiltonian defined as \( H=\lambda \vec{S}_1\cdot \vec{S}_2 \), if \( \lambda > 0 \), the spins must be anti-aligned to minimize energy, while if \( \lambda < 0 \), the spins are aligned. The ground state of the helium atom is a spin singlet state, indicating anti-aligned spins. Thus, the determination of the ground state configuration is contingent upon the specific spin-spin interaction defined by the Hamiltonian.

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In a past physics gre question (https://www.physicsforums.com/showthread.php?t=192334), we make use of the idea that the ground state energy of two ions that have spin is when the spins are aligned.

However, the ground state of the helium atom is a spin singlet state, which is a linear combo of two spins ANTI-aligned.

Can anyone please explain this discrepancy to me? Thank you!
 
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Which state is the ground state depends on the expression for the Hamiltonian. Take for example the easiest spin-spin interaction for two particles:
$$
H=\lambda \vec{S}_1\cdot \vec{S}_2.
$$
Suppose [itex]\lambda>0[/itex], then, in order to minimize the energy you want [itex]\vec{S}_1\cdot \vec{S}_2<0[/itex], i.e. anti-alligned spins. On the other hand if [itex]\lambda<0[/itex] you want the spins to be alligned.

So, there is no definitive way of determining if the ground state is same- or opposite-spins. It depends on the interaction.
 
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well, you can't have two electrons in the same spin state if they have the same quantum numbers for everything else, since they are fermions.
 

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