- #1

- 12

- 0

C

j . For this to hold p>= j. (j= integer). What happens if p=1/2,-1/2 or any other fraction? How can one use the same combination coefficient formula?

tks for any hlp.

- Thread starter suku
- Start date

- #1

- 12

- 0

C

j . For this to hold p>= j. (j= integer). What happens if p=1/2,-1/2 or any other fraction? How can one use the same combination coefficient formula?

tks for any hlp.

- #2

CompuChip

Science Advisor

Homework Helper

- 4,302

- 47

Is that true?

As far as I know, you cannot write

[tex]\sqrt{1 + x} = (1 + x)^{1/2}[/tex]

as

[tex]a 1^{1/2} + b x^{1/2} = a + b \sqrt{x}[/tex]

for any numbers a, b, for example.

You can write it as

[tex]\sqrt{1 + x} = a_0 + a_1 x + a_2 x^2 + \cdots[/tex]

but not with a finite series and a

The fact that it works with integers, is simply because you can open the brackets in, say, (1 + x)

- #3

CRGreathouse

Science Advisor

Homework Helper

- 2,820

- 0

You need infinitely many terms in that case. Just continue to generate terms the usual way.What happens if p=1/2,-1/2 or any other fraction?

- Last Post

- Replies
- 3

- Views
- 5K

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 15

- Views
- 1K

- Replies
- 5

- Views
- 733

- Last Post

- Replies
- 2

- Views
- 725

- Last Post

- Replies
- 2

- Views
- 4K

- Replies
- 3

- Views
- 9K

- Last Post

- Replies
- 2

- Views
- 3K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 3K