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In the triangle ABC the point D lies on the side BC and point E on the side AB. BD = AC, AD = AE and AB ^ 2 = AC * BC. Show that \angle BAD = \angle CEAView attachment 4777
In triangle ABC, with point D on side BC and point E on side AB, the conditions BD = AC, AD = AE, and AB² = AC * BC are established. These conditions lead to the conclusion that the angles ∠BAD and ∠CEA are equal. This geometric relationship is crucial for understanding angle congruence in triangles and can be proven using properties of similar triangles and the Law of Cosines.
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