Inclination angle between the orbital plane and the plane of the sky

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SUMMARY

The discussion centers on calculating the inclination angle between the orbital plane and the plane of the sky for celestial bodies. The user has an inclination angle of i = 40 degrees in the direct sense and seeks to find the corresponding indirect angle. The correct calculation for the indirect angle is established as 180 - 40, resulting in an indirect angle of 140 degrees. This interpretation aligns with the defined ranges for direct and indirect angles.

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Homework Statement



I have the inclinination i which is the angle between the orbital plane and the plane of the sky, i [0,pi/2] if it is in the direct sense ans [pi/2, pi] in the indirect, so here i have an angle i=40 in the direct sense how can i calculate the i in the indirect sense

Homework Equations

The Attempt at a Solution


i don't know maybe 180-40=140
 
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If I am interpreting your context correctly, you're asking about orbital inclinations in the context of celestial bodies. If you defined the direct and indirect angles to be as such, then yes it seems that it is a matter of 180-40. Do give us a bit more context though, it will be helpful :)
 
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