Projectile launched from an inclined plane strikes a wall horizontally

Click For Summary

Homework Help Overview

The problem involves a projectile launched perpendicularly from an inclined plane at an angle of 37° to the horizontal, aiming to determine the time it takes to strike a wall positioned at the foot of the incline. The projectile's motion is analyzed in relation to both the ground and the inclined plane.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the differences in analyzing the projectile's motion using different coordinate systems, questioning the validity of taking the y-component of velocity as zero at maximum height when the y-axis is defined perpendicular to the incline.

Discussion Status

Participants are exploring various interpretations of the problem, particularly regarding the orientation of the axes. Some guidance has been offered on how to approach the problem with the y-axis aligned with the wall, while others suggest considering the relationship between the x and y components of velocity at impact.

Contextual Notes

There is an ongoing discussion about the implications of choosing different coordinate systems and how it affects the calculations. Participants are also reflecting on the assumptions made regarding the projectile's motion and its interaction with the wall.

subhradeep mahata
Messages
120
Reaction score
13

Homework Statement


upload_2019-1-20_10-25-57.png

There is an inclined plane which is inclined at an angle of 37° to the horizontal. A projectile is projected perpendicularly to the inclined plane at a velocity of 50m/s such that it strikes a wall kept at the foot of the inclined plane perpendicularly. Find the time taken to reach the wall.

Homework Equations

The Attempt at a Solution


I have correctly done this problem when we consider the x and y-axis vertically (wrt ground). The trick in this problem is that it has reached the maximum height just when it strikes the wall.
But, I am not getting the correct answer when I consider the x and y-axis along the inclined plane. My "faulty" method is described below:
upload_2019-1-20_10-32-15.png

As it reaches max height, y component of velocity decreases from 50 to 0. So, applying v=u+at in y-direction,
0=50+(-gcos37°)(t)
or, t=6.25 sec , which is 2.25 seconds more than what i got as the correct answer in my first method.
Please see where i went wrong.
 

Attachments

  • upload_2019-1-20_10-25-57.png
    upload_2019-1-20_10-25-57.png
    22.4 KB · Views: 693
  • upload_2019-1-20_10-32-15.png
    upload_2019-1-20_10-32-15.png
    23.8 KB · Views: 447
Physics news on Phys.org
subhradeep mahata said:
As it reaches max height, y component of velocity decreases from 50 to 0.
When the y-axis is perpendicular to the incline, is it correct to take the y-component of velocity to be zero at maximum height above the floor?
 
I can't find anything wrong. Please explain.
 
The projectile is moving perpendicular to the wall when it hits the wall. If a vector is perpendicular to the wall, it can't also be perpendicular to your y-axis. Therefore, the vector cannot have a zero y-component.
 
All right, got it.
So, basically it is sensible to take the y-axis parallel to the wall like in my first method, isn't it?
Is there any way to proceed from here?
 
subhradeep mahata said:
All right, got it.
So, basically it is sensible to take the y-axis parallel to the wall like in my first method, isn't it?
Yes. I think it is easiest to have the y-axis parallel to the wall.
Is there any way to proceed from here?
You can work the problem with the y-axis chosen perpendicular to the incline. You will need to think about the relation between the x and y components of the velocity at the moment the projectile hits the wall.
 
Okay, I will try it.
@TSny Thank you very much.
 
You are welcome. Have fun with it.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K