Inclined Surface: Velocity and angle of incline

Click For Summary
SUMMARY

The discussion focuses on the relationship between the angle of incline and the acceleration of a car moving down an inclined surface. Participants confirm that the gravitational potential energy (mgh) converts into kinetic energy (1/2 mv^2), establishing that the velocity can be calculated using the formula v = sqrt(2gh). The acceleration of the car is directly related to the sine of the incline angle (g = a*sin(angle)), and the height (h) can be expressed as h = length*sin(θ). This establishes a clear mathematical relationship between incline angle, height, and acceleration.

PREREQUISITES
  • Understanding of gravitational potential energy (mgh)
  • Familiarity with kinetic energy equations (1/2 mv^2)
  • Knowledge of trigonometric functions, specifically sine
  • Basic grasp of kinematics and the suvat equations
NEXT STEPS
  • Study the derivation of the kinematic equations in physics
  • Learn about energy conservation principles in mechanics
  • Explore the application of trigonometry in physics problems
  • Investigate the effects of friction on inclined plane motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for clear explanations of incline dynamics.

Svensken
Messages
28
Reaction score
0

Homework Statement



How is angle of incline related to the acceleration of the car moving down it?

I know how to find both the velocity and acceleration of a car moving down a track using the suvat equations. I don't understand the relationship between angle of incline, velocity and gravity.

Basically, how does increased gravitational PE affect velocity?

Homework Equations



mgh
2s/t=v

The Attempt at a Solution



I think it has something to do with cosine of the angle as well as 1/2mv^2

Thank you guys and Gals!
 
Physics news on Phys.org
Spit the weight of the car into components perpendicular to the plane and parallel to the plane.

Also, how would you find the height the car is at when you know the length of the incline?
 
i was thinking:

mgh turns into 1/2 mv^2 (i am neglecting friction)

rearranging gives
v = sqroot(2gh)

Since g is equal to acceleration due to gravity it becomes g =a*sin(angle)

Is this correct?
 
Svensken said:
i was thinking:

mgh turns into 1/2 mv^2 (i am neglecting friction)

rearranging gives
v = sqroot(2gh)

yes but say you only had the length of the incline and the angle θ, what would h in terms of that length and θ?

Svensken said:
Since g is equal to acceleration due to gravity it becomes g =a*sin(angle)

Is this correct?

This is correct for the car's acceleration parallel to the plane
 
rock.freak667 said:
what would h in terms of that length and θ?

i would assume that h= length*sinθ?

This is correct for the car's acceleration parallel to the plane

Parallel meaning moving down the plane?

Thanks mate!
 

Similar threads

Replies
11
Views
1K
  • · Replies 36 ·
2
Replies
36
Views
6K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 9 ·
Replies
9
Views
4K