# Inclined Surface: Velocity and angle of incline

• Svensken
In summary, the angle of incline and acceleration of a car moving down it are related through the cosine of the angle and the equation 1/2mv^2. The height of the car can be found using the length of the incline and the angle θ, with the equation h = length*sinθ. The car's acceleration parallel to the plane is equal to the acceleration due to gravity multiplied by the sine of the angle.

## Homework Statement

How is angle of incline related to the acceleration of the car moving down it?

I know how to find both the velocity and acceleration of a car moving down a track using the suvat equations. I don't understand the relationship between angle of incline, velocity and gravity.

Basically, how does increased gravitational PE affect velocity?

mgh
2s/t=v

## The Attempt at a Solution

I think it has something to do with cosine of the angle as well as 1/2mv^2

Thank you guys and Gals!

Spit the weight of the car into components perpendicular to the plane and parallel to the plane.

Also, how would you find the height the car is at when you know the length of the incline?

i was thinking:

mgh turns into 1/2 mv^2 (i am neglecting friction)

rearranging gives
v = sqroot(2gh)

Since g is equal to acceleration due to gravity it becomes g =a*sin(angle)

Is this correct?

Svensken said:
i was thinking:

mgh turns into 1/2 mv^2 (i am neglecting friction)

rearranging gives
v = sqroot(2gh)

yes but say you only had the length of the incline and the angle θ, what would h in terms of that length and θ?

Svensken said:
Since g is equal to acceleration due to gravity it becomes g =a*sin(angle)

Is this correct?

This is correct for the car's acceleration parallel to the plane

rock.freak667 said:
what would h in terms of that length and θ?

i would assume that h= length*sinθ?

This is correct for the car's acceleration parallel to the plane

Parallel meaning moving down the plane?

Thanks mate!