1. The problem statement, all variables and given/known data A window washer pulls themself upward using a bucket/single pulley system. Their weight with the bucket is 65 Kg. a) How hard must she pull doward to raise herself slowly at a constant speed? b) If they increase the force by 15% what will her accelertion be? 2. Relevant equations 2Ft - mg = ma a = (Mb - Mp)/(Mb+Mp) .... I think 3. The attempt at a solution a) I've got no problem... to get constant speed accel = 0 so.... 2Ft - mg = 0 2Ft = mg Ft = mg/2 -> (65)(9.8)/2 = 320 N b) This is where I think I have the wrong equation to attempt this as (320)(0.15)= 48, so ..... [(368-320)/(368+320)](9.8)= 0.68 m/s^2 answer in the book is 1.5 m/s^2 so need something else but don't know what to use.