Undergrad Independent functions as solutions

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The discussion centers on the solutions to the Cauchy equation, specifically the independent functions r^2, r^(-3), and (1/7)r^6. It is clarified that while three functions were identified, a second order linear differential equation can only have two independent solutions. The term (1/7)r^6 is shown not to be a valid solution, as substituting it into the equation yields a discrepancy in the coefficients. The calculations demonstrate that the derived expression does not match the required form, confirming the inconsistency. Thus, the conclusion emphasizes that only two independent solutions exist for the given differential equation.
Sathish678
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TL;DR
I found three independent functions as solutions for this equation
d/dr(r^2dR/dr) = 6R (cauchy equation)
r^2 , r^(-3) , (1/7)r^6.
I found three independent functions as solutions for this equation
d/dr(r^2dR/dr) = 6R (cauchy equation)
r^2 , r^(-3) , (1/7)r^6.
But i read that a second order linear differential eqn has only two independent solutions.
Why this happened?
 
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\frac17 r^6 is not a solution. If it were, then as the equation is linear and homogenous r^6 must itself be a solution. It is not: <br /> \frac{d}{dr} \left(r^2 \frac{d}{dr}(r^6) \right) = \frac{d}{dr} \left( 6 r^7 \right) = 42r^6 \neq 6r^6.
 
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In a bit mote detail, if R= \frac{1}{7}r^6 then \frac{dR}{dr}= \frac{6}{7}r^5. So r^2\frac{dR}{dr}= \frac{6}{7}r^7 and then \frac{d}{dr}\left(r^2\frac{dR}{dr}\right)= 6r^6. That is NOT equal to 6R because it is missing the "\frac{1}{7}".
 
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