- #1
xdeimos
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why inductance's current represent with di/dt?
ps) and how do you make image big...
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Inductance: Why Does Di/Dt Represent Current?
- Thread starter xdeimos
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SUMMARY
The discussion centers on the relationship between inductance and current, specifically how the formula for voltage across an inductor is expressed as V = L(di/dt). A constant voltage applied to an ideal inductor results in a constant rate of change of current (di/dt). However, in real inductors, resistive elements can lead to voltage without a corresponding change in current, which is crucial for accurate circuit analysis.
PREREQUISITES- Understanding of inductance and its role in electrical circuits
- Familiarity with the formula V = L(di/dt)
- Knowledge of ideal versus real inductors
- Basic principles of circuit analysis
- Research the characteristics of ideal inductors versus real inductors
- Study the implications of resistive elements in inductors on circuit performance
- Explore advanced circuit analysis techniques involving inductance
- Learn about the applications of inductors in various electrical systems
Electrical engineers, circuit designers, and students studying electromagnetism and circuit theory will benefit from this discussion.
why inductance's current represent with di/dt?
ps) and how do you make image big...
- #2
meBigGuy
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Actually the Voltage is Ldi/dt. But I'm not sure that is all you are asking.
A constant voltage across an inductor will cause a constant change in current (di/dt) ... and vice-versa.
No idea about the images, but they expand when people click on them.
A constant voltage across an inductor will cause a constant change in current (di/dt) ... and vice-versa.
No idea about the images, but they expand when people click on them.
- #3
Windadct
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Make that an Ideal inductor - real inductor's restive elements can have V with no dI/dt... fine for circuit analysis, but in a real circuit this should always be considered.
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