Induction and the Fibonacci Sequence

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To prove the Fibonacci sequence using induction, start by verifying the base case for n=0. The induction step involves assuming the formula holds for n=k and then demonstrating it for n=k+1 by plugging k+1 into the recurrence relation F_{n}=F_{n-1}+F_{n-2}. It's important to note that you do not add another term but rather apply the recurrence relation directly. The discussion also highlights that using an explicit formula for the Fibonacci sequence may not lend itself well to induction, as it involves solving a quadratic equation rather than straightforward induction steps. Ultimately, clarity on the specific goal of the proof is essential for determining the correct approach.
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Homework Statement


If i want to use induction to prove the Fibonacci sequence I first check that 0 satisfies both sides of the equation. then i assume its true for n=k then show that it for works for n=k+1

The Attempt at a Solution


But I am a little confused if i should add another term or just plug in k+1
so the Fibonacci sequence is F_{n}=F_{n-1}+F_{n-2}
so then should k+1 be F_{k+1}= F_{k}+F_{k-1}+F_{k-2}
or should it beF_{k+1}=F_{k}+F_{k-1}
 
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Of course, you 'plug in' k+1. You don't add another term. It's not exactly clear what you are trying to prove here.
 
ok for example if we have 1+2+3+4+...n= n(n+1)/2
ow we assume its true for n=k and then plug in k=k+1 but on the left side we add the k+1 term to to previous sequence but on the right we plug in k+1
so we get 1+2+3+4+...k+(k+1)=(k+1)(k+1+1)/2
but with the Fibonacci sequence It seems a little strange to me
do i just add the next term or plug k+1 into all the terms?
 
cragar said:
ok for example if we have 1+2+3+4+...n= n(n+1)/2
ow we assume its true for n=k and then plug in k=k+1 but on the left side we add the k+1 term to to previous sequence but on the right we plug in k+1
so we get 1+2+3+4+...k+(k+1)=(k+1)(k+1+1)/2
but with the Fibonacci sequence It seems a little strange to me
do i just add the next term or plug k+1 into all the terms?

This all depends on what you are trying to prove. In this example, the left side is a sum, so sure, to go to the n+1 case you need to add a term. The right side is the formula for the sum, so to go to the n+1 case you change n to n+1. What exactly are you trying to prove about the Fibonacci sequence??
 
ok so the Fibonacci sequence is
F_{n}= \frac{a^{n+1}-b^{n+1}}{w}
so F_n is the formula for the sequence and a,b,w are fixed numbers and n is any integer and I am trying to prove the sequence with induction only I am not sure where to put the n+1
 
cragar said:
ok so the Fibonacci sequence is
F_{n}= \frac{a^{n+1}-b^{n+1}}{w}
so F_n is the formula for the sequence and a,b,w are fixed numbers and n is any integer and I am trying to prove the sequence with induction only I am not sure where to put the n+1

Ok, so you are talking about an explicit formula for the Fibonacci sequence. You put x^(n+1) into the recurrence relation for the Fibonacci sequence. You'll get a quadatic formula for value of x which has two solutions, call them a and b. Find them. Then you know c*a^(n+1)+d*b^(n+1) also satisfies the recurrence relation for any c and d. Now use the initial conditions F_0=1 and F_1=1 to fix c and d. There's really no 'induction' in this derivation. I think it would be really awkward to try to show this by induction.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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