Inductor Currents: Find L for 15kHz Oscillator & 6V RMS, 65mA Peak

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SUMMARY

The discussion centers on calculating the inductance (L) for an inductor connected to a 15 kHz oscillator with a peak current of 65 mA and an RMS voltage of 6.0 V. The formula used is Il = Vl / Xl, where Xl = frequency * L. The correct calculation involves converting the RMS voltage to peak voltage by multiplying by the square root of 2, leading to the correct inductance value. The initial incorrect answer of 0.979 mH was due to neglecting this conversion.

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Homework Statement


An inductor is connected to a 15 kHz oscillator. The peak current is 65 mA when the rms voltage is 6.0 V. What is the value of the inductance L? In mH


Homework Equations


Il=Vl/Xl
Xl=frequency*L

The Attempt at a Solution


Well I thought this problem was really straight forward just convert everything to similar units and plug in but I keep getting .979 mH and it says that answer is wrong so was hoping someone could help me out here.
 
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No need to help me on this problem I figured it out I didn't notice the rms on the voltage so I forgot to multiply by square root of 2
 

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