RLC Circuit Homework: Find L, Z, I, and P

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Homework Help Overview

The discussion revolves around a series RLC circuit with given resistance, capacitance, and resonance frequency. Participants are exploring the calculations for inductance, impedance, rms current, and average power consumed at resonance.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants attempt to calculate inductance using the resonance frequency formula and question the units of capacitance. There are discussions about the power factor and its implications on average power calculations. Some participants express uncertainty regarding their calculations and seek validation of their reasoning.

Discussion Status

The discussion is active, with participants providing feedback on each other's calculations and clarifying concepts such as the power factor. There is acknowledgment of typos and corrections, but no consensus has been reached on the overall correctness of the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share or the depth of their discussions. There is a noted discrepancy in the units of capacitance that could affect calculations.

SilverAu
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Homework Statement


A series RLC circuit has R=75 ohms, C=20 mF and a resonance frequency of 5.0 kHz. (i) What is the value of inductance? (ii)What is the impedance of the circuit at residence? (iii)What is the rms current at resonance if the rms voltage of the power supply is 120 V? (iv) How much average power is consumed in the circuit at resonance?

Homework Equations


f=1/(2π√LC), z= √(XL-XC)^2 +R^2, I=V/Z and P=VI [/B]

The Attempt at a Solution


(i) What is the value of inductance?
f=1/(2π√LC)
L=1/4π^2 * 1/f^2C
1/(4π^2) * 1/[(50e3)^2(20^-6)]
L=5.07 e-7 H
(ii)What is the impedance of the circuit at residence?
z= √(XL-XC)^2 +R^2
z= √WL-1/WC)^2 +R^2
z= √[(314e3 * 5.07e-7)-(1/314e3 * 20e-6)]^2 +5^2
z= 75 Ohms
(iii)What is the rms current at resonance if the rms voltage of the power supply is 120 V?
I=V/Z
I=120/75
I=1.6 A
(iv) How much average power is consumed in the circuit at resonance?
P=VI
P=120* 1.8
P=192 W[/B]
 
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What is your question about the problem? :)

Have you thougth about the power factor in (iv)?
 
Alettix said:
What is your question about the problem? :)

Have you thougth about the power factor in (iv)?
I just wanted to know if I was correct. Whether my process of thinking was correct and the numbers backed it up. The power factor is just p=1/2 VI cosϕ, correct? so is it then 1/2 [120*1.8 cos (0)]= 96 W.
 
SilverAu said:
A series RLC circuit has R=75 ohms, C=20 mF and a resonance frequency of 5.0 kHz. (i) What is the value of inductance? (ii)What is the impedance of the circuit at residence? (iii)What is the rms current at resonance if the rms voltage of the power supply is 120 V? (iv) How much average power is consumed in the circuit at resonance?
Are the capacitor units mF or μF? There's a 1000 times difference...
 
gneill said:
Are the capacitor units mF or μF? There's a 1000 times difference...
sorry microfarad (µF)
 
SilverAu said:
.The power factor is just p=1/2 VI cosϕ, correct? so is it then 1/2 [120*1.8 cos (0)]= 96 W.

Because there is resonance, the power factor is cos(0) = 1.
The average power is given by: P = Irms * Vrms * cos(θ)
so in your case: P = Irms * Vrms
If your calculated values for Vrms and Irms are right the power should be: P = 120 * 1,6 = 192 W as you have written.
(So I guess it was a typo to write P = 120 * 1,8 = 192 W :) )

I haven't checked the rest of the calculation in detail, but this part appears right to me.
 
Alettix said:
Because there is resonance, the power factor is cos(0) = 1.
The average power is given by: P = Irms * Vrms * cos(θ)
so in your case: P = Irms * Vrms
If your calculated values for Vrms and Irms are right the power should be: P = 120 * 1,6 = 192 W as you have written.
(So I guess it was a typo to write P = 120 * 1,8 = 192 W :) )

I haven't checked the rest of the calculation in detail, but this part appears right to me.
Yes, apologies it was a typo it is 1.6*120=192 W. If you could please check the rest of my work it would be great because this problem has been a pain in my side for a couple of days (:
 
SilverAu said:
z= √WL-1/WC)^2 +R^2
z= √[(314e3 * 5.07e-7)-(1/314e3 * 20e-6)]^2 +5^2

One more typo here (R=75Ω, and not R=5Ω), but otherwise I think it's right.
 
Alettix said:
One more typo here (R=75Ω, and not R=5Ω), but otherwise I think it's right.
Yes another typo lol...Thank you so much, all your help is greatly appreciated!
 

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