1. The problem statement, all variables and given/known data A mass M slides down a smooth surface from height h and collides inelastically with the lower end of a rod that is free to rotate about a fixed axis at P as shown below. The mass of the rod is also M, the length is L, and the moment of inertia about P is ML2/3. The angular velocity of the rod about the axis P just after the mass sticks to it will be: (A) √(gh/2) (B) √(2gh)/L (C) (3/4L)√(2gh) (D) (3L)/√(2gh) (E) (9√(2gh))/L 2. Relevant equations There's a bunch. 3. The attempt at a solution I started with conservation of energy, so mgh=(1/2)mv2 and thus v=√(2gh). I don't really know where to go next. I know inelastic means momentum is conserved and kinetic energy is not.