Inelastic collision followed by circular motion

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SUMMARY

The discussion centers on the analysis of an inelastic collision followed by circular motion, with a calculated post-collision speed of 2.25 m/s for the masses involved. Participants explore the subsequent behavior of the masses as they transition to circular motion, identifying three distinct possibilities for their trajectory. The conversation emphasizes the importance of understanding the dynamics of both inelastic collisions and circular motion in physics.

PREREQUISITES
  • Understanding of inelastic collisions in physics
  • Knowledge of circular motion dynamics
  • Familiarity with basic kinematic equations
  • Ability to analyze forces acting on moving bodies
NEXT STEPS
  • Research the principles of conservation of momentum in inelastic collisions
  • Study the equations governing circular motion, including centripetal force
  • Explore the effects of mass and velocity on circular trajectories
  • Investigate real-world applications of inelastic collisions and circular motion in engineering
USEFUL FOR

Students of physics, educators teaching mechanics, and engineers involved in motion analysis will benefit from this discussion.

Sal Coombs
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Homework Statement
A 3.0-kg mass is sliding on a horizontal frictionless surface with a speed of 3.0 m/s when it collides with a 1.0-kg mass initially at the bottom of a circular track. The masses stick together and slide up a frictionless circular track of radius 0.40 m. To what maximum height, h, above the horizontal surface (the original height of the masses) will the masses slide?
Relevant Equations
mv = mv Momentum
1/2mv^2 Kinetic Energy
mgh Potential Energy
(mv^2)/r Centripetal Force
Found the speed at which the masses will travel after their collision: 2.25m/s
Not sure what to do next...
 
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Sal Coombs said:
Found the speed at which the masses will travel after their collision: 2.25m/s
Not sure what to do next...
What happens when the masses follow the circular track?
 
To expand on @PeroK's question, there are three distinct possibilities. Can you list them?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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