Can total KE ever increase for inelastic collisions?

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vcsharp2003
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Homework Statement


Is following statement True or False?
For inelastic collusions, the total KE of colliding objects just after collision is less than the total KE just before collision.
The answer is given as False with a mention saying: "This is normally true but in some cases it could increase(why?)".

Homework Equations



Total KE initial = Total KE final
The above is true only for elastic collisions.

The Attempt at a Solution


For inelastic collisions, some of the KE is always lost and therefore total KE of colliding objects must decrease.

The only way that total KE could increase is when some of the mass of colliding objects gets converted to KE, but not sure if this really happens.
 
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http://physics.stackexchange.com/qu...c-collision-where-final-kinetic-energy-of-the

TL;DR. Yes, but you need a source of energy that gets released upon collision (e.g. chemical energy in gunpowder, spring getting released). If you're looking at 2 ordinary blocks, you're always going to have KE decrease after an inelastic collision. Where there is an increase in KE in a closed system, there is always a source: Potential energy, chemical energy, mass energy even...
 
Socrates said:
http://physics.stackexchange.com/qu...c-collision-where-final-kinetic-energy-of-the

TL;DR. Yes, but you need a source of energy that gets released upon collision (e.g. chemical energy in gunpowder, spring getting released). If you're looking at 2 ordinary blocks, you're always going to have KE decrease after an inelastic collision. Where there is an increase in KE in a closed system, there is always a source: Potential energy, chemical energy, mass energy even...
But isn't mass a source of energy? Maybe in some collisions involving sub-atomic particles, mass gets converted to energy.
 
vcsharp2003 said:
But isn't mass a source of energy? Maybe in some collisions involving sub-atomic particles, mass gets converted to energy.

Correct. I've personally never studied relativistic collisions that resulted in a decrease of mass and an increase of KE (although an exploding atomic bomb certainly converts mass to KE). In classical physics, especially in the low-energy limit, mass is conserved in collisions, so classical examples of an increase in KE would be if you triggered the release of a compressed spring during the collision.
 
Socrates said:
so classical examples of an increase in KE would be if you triggered the release of a compressed spring during the collision.
In the case of an expanding spring tied to a block A that is expanding when this block A collides with another block B, how could we say that it's an inelastic collision? Is it that collisions in real life are usually inelastic since some energy always dissipated?
 
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vcsharp2003 said:
In the case of an expanding spring tied to a block A that is expanding when this block A collides with another block B, how could we say that it's an inelastic collision?
Because kinetic energy is not conserved. The KE of block A plus the KE of block B is increased as a result of the collision. An "elastic collision" is one in which KE is conserved. An "inelastic collision" is one in which it is not.

[I assume that you have in mind a spring that is compressed and which is released during the collision so that it imparts its stored potential energy to the blocks]
Is it that collisions in real life are usually inelastic since some energy always dissipated?
That is usually the case. However it is not relevant to classifying a collision in which kinetic energy increases.
 
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