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I've been on the question for a while and I'm not quite sure where I'm going wrong. If someone could help me out, I'd really appreciate it!

Problem

Two ice-fishermen are driving trucks across a frozen and frictionless lake. Truck 1 (m1 = 1190kg) is traveling with a speed of 13.2m/s in a direction of 43.0degrees SOUTH of EAST. Truck 2 (m2 = 1000kg) is traveling due NORTH with a speed of 20.1m/s. The trucks collide and lock into a single unit. What is the speed of the joined trucks immediately after the collision?

2. Relevant equations

equation for inelastic collision...

Vf = (m1V1i + m2V2i) / (m1 + m2)

3. The attempt at a solution

I have tried it a couple of ways so far, and neither have worked.

First, I tried just plugging in the velocities without using the angle.

Vf = (1190kg*13.2m/s + 1000kg*20.1m/s) / (1190kg + 1000kg)

= 16.4 m/s (wrong answer!!)

Then I tried incorporating the y-coordinate angle however I'm not sure if I did this properly.

Vf = (1190kg*13.2m/s(sin43) + 1000kg*20.1m/s) / (1190kg + 1000kg)

= 14.1 m/s (wrong again!!)

If you could offer me any help, it would be greatly appreciated!

:)

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# Homework Help: Inelastic Collision Question

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