Inequality question (when fraction < zero)

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SUMMARY

The inequality to solve is [-2(t²+1) / 9(t²-1)] < 0. The solution intervals are confirmed as -∞ < t < -1 and 1 < t < ∞. The fraction's sign is determined by the signs of its factors, with the denominator changing signs at t = -1 and t = 1. By testing values in the intervals, one can deduce the sign of the fraction, leading to the correct intervals for t.

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Homework Statement



Solve for t:

[-2(t2+1) / 9(t2-1)] < 0

The Attempt at a Solution



I know that the answer is -inf<t<-1 and 1<t<inf, but how do I show the calculation to get that answer? When I tried, I narrowed it down to t<root-1, but that's not possible (without complex numbers) and doesn't match the answer?
 
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Try factoring the denominator and analyzing the signs of the factors.
 
So 9(t-1)(t+1), but what do I deduce from that?
 
page13 said:
So 9(t-1)(t+1), but what do I deduce from that?


The sign of a fraction is determined by the signs of its factors. You have a - in front of the fraction and the t2 + 1is always positive. The only places where the denominator changes signs are at 1 and -1. So figure out the signs everywhere else. Wherever you have an even number of negative signs your fraction is negative and an odd number makes it positive.
 
Ah OK. So it's more by inspection. I would factor as we have done, and then I'd choose for example -2, 0 and 2 and determine the sign giving me the interval values around 1 and -1, correct?
 
That's the idea. Since those factors can only change sign at their roots, if you check the values at a point on each subinterval you will know the signs on the intervals.
 
Awesome. Thanks. Now I can sketch this parametric.
 

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