Infinite potential well and linear superposition

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Homework Help Overview

The discussion revolves around a quantum mechanics problem involving a particle in an infinite potential well. The wave function is expressed as a linear superposition of the first two stationary states, and participants are tasked with calculating the probability density, expectation values, and probabilities associated with the states.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the wave function and its complex conjugate, exploring how to ensure the resulting probability density is real. There are attempts to simplify expressions using Euler's formula and to identify the frequency of oscillation in the probability density.

Discussion Status

Some participants have made progress in expressing the wave function and its conjugate, while others are seeking clarification on the implications of their calculations. There is an ongoing exploration of the relationship between the expectation value of the Hamiltonian and the energy eigenvalues, as well as how to determine the probabilities for the particle being in specific states.

Contextual Notes

Participants express uncertainty regarding the simplification of complex terms and the calculation of probabilities, indicating a need for further guidance on these aspects. There is also mention of potential mistakes in calculations, particularly concerning signs in the expressions.

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Homework Statement



Consider a particle in a potential ;
[tex]V(x)=0\ for\ 0<=x<=L[/tex] and
[tex]V(x)=\infty\ otherwise[/tex]

. Its wave function is a linear superposition of the lowest two stationary states and given by
[tex]\psi(x,t)=\frac{1}{2}*(\sqrt{3} \psi_{1}(x,t)-\psi_{2}(x,t)[/tex])

(a) Use the results fromquestion 2 and find ψ(x,t). Then calculate [tex]|\psi(x,t)|^{2}[/tex].
Make sure that your result for [tex]|\psi(x,t)|^{2}[/tex] is manifestly real (no “i” left in there). What is the frequency of the oscillation in [tex]|\psi(x,t)|^{2}[/tex]?

(b) Calculate the expectation value of the Hamilton operator ˆH. Compare it with the energy eigenvalues
E1 and E2.

(c) What is the probability for the particle to be in state ψ1 and what is the probability for it to be in the state ψ2?

Homework Equations



Time dependent wave function for the nth stationary state in this potential well in this case is;
[tex]\psi_{n}(x,t)=\sqrt{\frac{2}{L}}\sin(\frac{n\pix}{L})\exp{\frac{-iE_{n}t}{h/2\pi}\ n=1,2,3,...[/tex]
and
[tex]E_{n}=\frac{h^{2}n^{2}}{8mL^{2}}[/tex]

The Attempt at a Solution



Hi, I can get the solution to the first part of (a), I think,

[tex]\psi(x,t)=\frac{1}{2}(\sqrt{\frac{6}{L}}\sin(\frac{\pi\x}{L})\exp{\frac{-iE_{1}t}{h/2\pi}-\sqrt{\frac{2}{L}}\sin(\frac{2\pi\x}{L})\exp{\frac{-iE_{2}t}{h/2\pi})[/tex]

Where
[tex]E_{1}=\frac{h^{2}}{8mL^{2}}[/tex] and
[tex]E_{2}=\frac{h^{2}}{2mL^{2}}[/tex]

But after that I have no idea of where to go. When I try and calculate the product of the conjugate times non-conjugate I end up with complex terms that I can't simplify, so my result isn't real. Also I have no idea how you find the frequancy of oscillation in [tex]|\psi(x,t)|^{2}[/tex], or how to calculate the expectation of the Hamiltonian operator. Any help would be a godsend to me, I feel completely lost now in QM.

Thanks in advanc
 
Last edited:
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The complex conjugate of (a + ib) is (a - ib). So, the product of these two will give a real number. You stated your result has complex terms. Show how you took the product of the complex number and the conjugate.
 
The conjugate of this,

[tex]\psi(x,t)=\frac{1}{2}(\sqrt{\frac{6}{L}}\sin(\frac{\pi*x}{L})\exp{\frac{-iE_{1}t}{h/2\pi}-\sqrt{\frac{2}{L}}\sin(\frac{2\pi*x}{L})\exp{\frac{-iE_{2}t}{h/2\pi})[/tex]

will be,

[tex]\psi_{1}(x)*\bar{\phi_{1}(t)}-\psi_{2}(x)*\bar{\phi_{2}(t)}[/tex]

where [tex]\phi_{n}(t)=exp{\frac{-iE_{n}t}{h/2\pi}[/tex]

Now taking [tex][\psi_{1}(x)*\bar{\phi_{1}(t)}-\psi_{2}(x)*\bar{\phi_{2}(t)}]*[\psi_{1}(x)*{\phi_{1}(t)}-\psi_{2}(x)*{\phi_{2}(t)}][/tex]

Gives

[tex]\psi_{1}(x)^{2}-\psi_{1}(x)*\bar{\phi_{1}(t)}*\psi_{2}(x)\phi_{2}(t)-\psi_{2}(x)*\bar{\phi_{2}(t)}\psi_{1}(x)\phi_{1}(t)+\psi_{2}(x)^{2}[/tex]

since [tex]\phi_{1}(x)\neq\phi_{2}(x)[/tex] in general I have two mixed terms in the middle. How do I get rid of them? What have I done wrong?
 
One way of doing this is to express the compex exponential in terms of cosine and sine using the Euler relation. This will separate the real and imaginary parts then you can combine in the form a + ib. Then multiply by the conjugate giving a2 + b2.
 
Okay. I'm going to simplify everything and call the arguments of both exponential theta(1) and theta(2).

Expanding using Eulers notation gives,
[tex]\psi(x,t)=\frac{1}{2}*[\psi_{1}(x)cos{\theta_{1}}-\psi_{2}(x)cos{\theta_{2}+i(\psi_{2}\sin{\theta_{2}+\psi_{1}sin{\theta_{1})[/tex]

Thus, [tex]\bar\psi(x,t)*\psi(x,t)[/tex] is,

[tex]\frac{1}{4}(x^{2}+y^{2})[/tex]

where [tex]x=\psi_{1}(x)cos{\theta_{1}}-\psi_{2}(x)cos{\theta_{2}[/tex]
[tex]y=(\psi_{2}\sin{\theta_{2}+\psi_{1}sin{\theta_{1})[/tex]

Does this look alright now?
 
Looks fine with the exception that I get a minus sign between the sine terms since both arguments are negative.
 
Excellent thanks for the help, I will put the minus's in at the end since i always lose the damn things!

Now please could you give me a hint as to how I find the frequency of oscillation in [tex]\bar\psi(x,t)*\psi(x,t)[/tex]?

For part (b) I got the expectation of the Hamiltonian to be less than the sum of the energy eigenvalues. Is this right or have a made a mistake somewhere?


Also for part (c) how do I find the probability for the particle to be in either of the states?
 

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