Infinite Series: Determine Convergence/Divergence

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Homework Help Overview

The discussion centers around determining the convergence or divergence of the infinite series \(\sum\frac{7^{k}}{5^{k}+6^{k}}\) from \(k=0\) to infinity, focusing on the application of various convergence tests.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of the natural logarithm in the original poster's attempt, question the appropriateness of various convergence tests such as the root test, ratio test, and comparison test, and explore comparisons to geometric series.

Discussion Status

There is an active exploration of different methods to assess convergence, with some participants suggesting specific tests and others expressing uncertainty about their application. No consensus has been reached on a definitive approach yet.

Contextual Notes

Participants note challenges with the denominator in comparison tests and discuss the implications of using natural logarithms in their reasoning.

XJellieBX
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Homework Statement


\sum\frac{7^{k}}{5^{k}+6^{k}}
Determine if this infinite series (from k=0 to infinity) converges or diverges.


2. The attempt at a solution
I set ak=\frac{7^{k}}{5^{k}+6^{k}}
then I took the Ln of both sides
ln ak=ln\frac{7^{k}}{5^{k}+6^{k}}=ln7k-ln(5k+6k)

I'm not sure if I did it right or where to go from here.
 
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hi XjellieBX
do you know how to test for divergence or convergence?
 
we learned the root test, the ratio test, and the basic comparison test in class. but I'm not sure which one to use.
 
no need to take the natural log; that is making your life too hard. have you tried to look at a comparison test with a special type of series (geometric, p-series, harminic, alternating, etc)?
 
yes. i tried to compare it to the geometric series, but i was having some problems with the denominator
 
i think the ratio test would work well here
 
comparison test is ok, hint: 5^k+6^k<2*6^k
 

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