Infinite Series Test: 1/n^2 - 1/n^3

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SUMMARY

The discussion centers on the convergence of the infinite series \(\sum^{\infty}_{n=1} (1/n^2 - 1/n^3)\). Participants identify it as a telescoping series, but initial attempts to simplify the terms reveal no cancellations beyond the first terms. The conclusion drawn is that further analysis is required to determine whether the series converges or diverges, with an emphasis on applying appropriate convergence tests.

PREREQUISITES
  • Understanding of telescoping series
  • Familiarity with convergence tests in calculus
  • Knowledge of infinite series notation
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of telescoping series
  • Learn about the Ratio Test for convergence
  • Explore the Comparison Test for series
  • Review the concept of divergent series in calculus
USEFUL FOR

Students studying calculus, particularly those focusing on infinite series and convergence tests, as well as educators looking for examples of series analysis.

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Homework Statement


[tex]\sum[/tex][tex]^{infinity}_{n=1}[/tex] (1/n^2 - 1/n^3)

Homework Equations


it goes to infinity
n=1


The Attempt at a Solution


Im assuming this is a telescoping series. when I plugged in my terms nothing canceled out except for the 1's at the beginning.

(1-1)+(1/4 - 1/8)+(1/9 - 1/27)+...

Am I doing something wrong? Or does it just go to infinity and therefore diverge?
 
Last edited:
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You didn't say what you're supposed to do with this series, which would have been useful information.

Presumably you're supposed to determine that the series is divergent or it is convergent. What tests do you know of that you can use?

When you ask "does it just go to infinity", what are you referring to by "it"? Whatever "it" is, why do you think "it" goes to infinity? There's nothing in the work you show that suggests that to me.
 

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