Infinite Sum: What Does b Converge To?

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SUMMARY

The infinite sum \(\sum \frac{(-1)^n \cdot b^{2n+2}}{(2n+2)!}\) converges to \(1 - \cos(b)\) for any constant number \(b\). This conclusion is derived from the properties of Taylor series expansions, specifically the series for cosine. The discussion confirms that the convergence behavior is consistent across all values of \(b\).

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Marth361
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Converges to...

If "b" is any constant number, what does the infinite sum

[tex]\sum[/tex] [(-1)^n * b^(2n+2)] / (2n+2)!

converge to (in terms of "b")?
 
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If the sum goes from zero to infinty, then I would say

[tex] 1 - \cos(b)[/tex]
 

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