Infinitely long cylinder - locate bound currents and calculate field

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SUMMARY

The discussion focuses on calculating the magnetic field B inside and outside an infinitely long cylinder with a frozen-in magnetization M=ks k-hat, where k is a constant and s is the distance from the axis. Two methods are employed: locating bound currents and using Ampere's law. It is established that the magnetic field B outside the cylinder approaches zero due to the cancellation of currents, similar to the behavior of an infinitely long solenoid. The Biot-Savart law is suggested for a more rigorous proof of this phenomenon.

PREREQUISITES
  • Understanding of magnetization and bound currents in materials
  • Familiarity with Ampere's law and its application
  • Knowledge of the Biot-Savart law for magnetic field calculations
  • Basic concepts of magnetic fields in solenoids and cylinders
NEXT STEPS
  • Study the application of the Biot-Savart law in different geometries
  • Explore the derivation of magnetic fields from bound currents in cylindrical coordinates
  • Learn about the implications of magnetization in materials and its effects on magnetic fields
  • Investigate the relationship between current loops and magnetic fields in solenoids
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Physics students, electrical engineers, and anyone studying electromagnetism, particularly those interested in magnetic fields generated by materials with magnetization.

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Homework Statement



An infinitely long cylinder, of radius R, carries a frozen-in magnetisation, parallel to the z-axis, M=ks k-hat, where k is a constant and s is the distance from the axis. There is no free current anywhere. Find the magnetic field B inside and outside the cylinder by two different methods:

i) Locate all bound currents, and calculate the field they produce; and
ii) Use Ampere's law, the loop integral of H.dl=I(subscript enc), to find H, then get Bfrom H=(1/mu0)B-M

The Attempt at a Solution


I found the answer on http://www.nhn.ou.edu/~shaferry/41832005_files/finalsol.pdf

but what I don't understand is why far away from the loop the B field must go to zero. I would be grateful if someone could explain please.
 
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but what I don't understand is why far away from the loop the B field must go to zero. I would be grateful if someone could explain please.[/QUOTE]

Same reason that B outside an infinitely long solenoid is zero. Looking at a given section of the solenoid, coil currents flow in opposite directions along the two sides of the solenoid, canceling the external field. A permanent-magnet cylinder is no different if magnetization is along the major axis (center). Amperian currents merely assume the role played by a solenoid's current-carrying wire.

So B doesn't just disappear at infinity, it disappears anywhere outside the OD of the rod.

This can be proven more rigorously by application of the Biot-Savart law.

cf. Resnick & Halliday, sect. 34-5.
 
the current loop need to enclose some sort of current for there to be any sort of magnetic field this is why outside a solenoid the B field is zero
 
That only means that the circulation (closed-path integral) of B is zero. It does not preclude segments of the path being finite, as long as they cancel around the path.

Example: a single loop of curent-carrying wire. Choose a closed path in front of the loop but not intersected by the loop. B is certainly not zero in front of the loop!
 
thanks,
for que i), why is the field due to the volume distribution=mu0 k(R-s)z-hat?
The bound current due to the volume is curl M=- k phi-hat, but how does this lead to:

the field due to the volume distribution=mu0 k(R-s)z-hat?
 
I'm sorry no one's replied to that, incl. me. Truth is, I don't know the answer without researching the subject more myself.
 
thanks anyway. think i found out in the end, though
 

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