Initial Velocity and Energy Conservation for Disk Collision

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SUMMARY

The discussion focuses on the conservation of momentum and energy during a collision between two disks, P and Q, with respective inertias of 0.41 kg and 0.75 kg. The initial velocity of disk P is unknown, while disk Q is at rest. The relevant equations for solving the problem include the conservation of momentum expressed as m1 v1i + m2 v2i = m1 v1f + m2 v2f, applicable in both x and y components. The discussion emphasizes the need to account for vector quantities in momentum calculations.

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Homework Statement


Disk P (inertia 0.41 kg ) moves at an unknown velocity across a low-friction horizontal surface and collides with disk Q (inertia 0.75 kg ), which is initially at rest. After the collision, the two (now slightly dented) disks move apart without spinning. Velocity information is provided in the initial and final top-view diagrams in the (Figure 1) .

What was the initial velocity of disk P?
What fraction of the initial kinetic energy is converted during the collision?
Mazur1e.ch10.p64.jpg


Homework Equations


v1im1 + v2im2 = v1fm1 + v2fm2

The Attempt at a Solution


So I know you use conservation of momentum, but I'm not entirely sure how to set up the equations to include theta.
 
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Momentum is a vector quantity. So, the relevant equation is a vector equation

m1 v1i + m2 v2i = m1 v1f + m2 v2f

In terms of x components:

m1 v1ix + m2 v2ix = m1 v1fx + m2 v2fx

(There is a similar equation for the y components.)
 

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