Very basic question but could someone briefly explain why the inner product for complex vector space involves the conjugate of the second vector. Of course if imaginary component is 0 then this reduces to dot product in real vector space. And I see that this definition makes sense to calculate "length" so that it is not a negative number. But is there another geometrical (using cosine?) or intuitively logical reason why the inner product is defined this way?(adsbygoogle = window.adsbygoogle || []).push({});

Thanks, Howard

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Inner Product for Vectors in Complex Space

Loading...

Similar Threads for Inner Product Vectors | Date |
---|---|

What is the largest number of mutually obtuse vectors in Rn? | Jan 28, 2016 |

Inner Product of Complex Vectors? | Jun 19, 2014 |

Inner Product Space of two orthogonal Vectors is 0 , Is this defined as it is ? | Dec 27, 2012 |

Maximum inner product between two orthgonal vectors (in standard dot procut)) | Apr 24, 2012 |

**Physics Forums - The Fusion of Science and Community**