DUET said:
Let,
u, v ε V
u=( 2, 4, 5, 7) and V = (1, 3, 4, 9)
Now what is the inner product of u and v?
I would request to discuss it by illustrating the following
[itex]\langle \cdot | \cdot \rangle: V\times V \rightarrow \mathbb{R}[/itex]̣
Is it mean inner product of the above two vector is -
u×v→r
No, it's to say that not u×v (that rarely means anything outside R
3 afaik), but the pair (u,v) ∈ V×V maps to ( ↦)
some specific real number r ∈ R. In addition to knowing from which space and to where the product is from, you must also know what inner product it is. That is, a rule according to which you actually calculate the product.
IF you consider, as an
example, the regular "dot product" in R
n, the inner product is [itex]<,> : {\mathbb{R}}^n \times {\mathbb{R}}^n \rightarrow \mathbb R[/itex] such that for [itex]u,v \in {\mathbb{R}}^n[/itex] the pair [itex](u,v) \in {\mathbb{R}}^n \times {\mathbb{R}}^n[/itex] and [itex](u,v)\mapsto \sum_{i=1}^n u_i v_i[/itex] which is the same as saying [itex]<u,v>=\sum_{i=1}^n u_i v_i[/itex].
In your specific example, with the regular dot product [itex]<u,v>=\sum_{i=1}^n u_i v_i=2\cdot 1+4\cdot 3+5\cdot 4+7\cdot 9=2+12+20+63=97[/itex], but notice that there are various different inner products in R
n, and you can't say anything about the value of <u,v> unless you specify the inner product. For R
n, it usually is the dot product, but it can be something else as well.
Notice that [itex]\sum_{i=1}^n u_i v_i\in \mathbb{R}[/itex]., as the components [itex]u_i,v_i[/itex] are all real numbers.