Instantaneous rate of change of a sphere

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SUMMARY

The discussion focuses on finding the instantaneous rate of change of the volume (V) of a sphere with respect to its radius (r) when r equals 5 micrometers. The volume formula used is V = (4/3)π(r^3). The correct approach involves taking the derivative of this formula, which results in dV/dr = 4πr^2. Evaluating this derivative at r = 5 micrometers yields a non-zero value, confirming that the rate of change is not zero.

PREREQUISITES
  • Understanding of calculus, specifically differentiation
  • Familiarity with the formula for the volume of a sphere
  • Knowledge of basic mathematical constants, such as π
  • Ability to evaluate derivatives at specific points
NEXT STEPS
  • Study the concept of derivatives in calculus
  • Learn how to apply the power rule for differentiation
  • Explore applications of derivatives in real-world scenarios
  • Practice finding rates of change for various geometric shapes
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Students studying calculus, particularly those learning about derivatives and rates of change, as well as educators seeking to explain these concepts in a practical context.

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Homework Statement


Find the instantaneous rate of change of V with respect to r when r=5 micrometers


Homework Equations



V=4/3pi(r^3)

The Attempt at a Solution



would you just take the derivative? and if so, wouldn't it just be zero, because it comes out to be a real number, right? but that doesn't seem right...
 
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What is the derivative of V=4/3pi(r^3)? Now what would the value be at r=5micrometers? Not zero.
 
ooh, I am an idiot, thanks
 

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