Instantaneous Speed & Acceleration: Equations Explained

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Homework Help Overview

The discussion revolves around the concepts of instantaneous speed and instantaneous acceleration, particularly focusing on their definitions and the equations used to calculate them. Participants explore the relationship between position, velocity, and acceleration through derivatives.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of derivatives to find instantaneous speed and acceleration from given equations of motion. Questions arise regarding the interpretation of variables in equations and how to apply them to specific instances, such as at certain time points.

Discussion Status

The discussion is active, with participants sharing insights about the mathematical relationships involved. Some guidance has been offered regarding the use of derivatives, but there remains uncertainty about applying these concepts to specific problems, particularly in interpreting the variables and their values.

Contextual Notes

There is mention of a specific problem involving a graph and the need to understand the slope at certain times, indicating a reliance on visual data that may not be fully described in the thread. Participants express confusion about variable definitions and how to proceed with calculations.

lostfan176
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how do you find instantaneous speed and instantaneous acceleration. is there an equation?
 
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instantaneous acceleration is the limit of change of velocity divided by change of time as the change of time goes to 0. Which is the derivative of velocity.

Usually you are given an equation for velocity or position and you take derivatives to get an equation for acceleration/velocity.

Instantaneous speed would be instantaneous velocity which is the derivative of the equation of the positioin of a particle without any direction.

So if you're given x=a+bt+ct^2 and asked for instanatenous velocity/acceleration at time t=1 you can just do:

dx/dt=b+2ct =v v(1) = b+2c
dv/dt=2c = a a(1)=2c
 
In Fig. P18, what was the car's instantaneous acceleration at t = 3.0 s? What was its instantaneous acceleration at t = 2.25 s?

3-P18.gif


so how would i use that equation to find the solution i don't know what the variables stand for
 
Last edited:
ok well the derivative is also the slope of the line tangent to the graph of a function at time t.

So looking at your graph what is the slope (i.e. change in y/x) at time t=4?

Edit: ok just saw the graph again o.o looked different before ><.

Hm...ok what does the acceleration do to velocity? velocity describes how fast position changes. so acceleration describes?
 
Last edited:
rate of change of velocity but like where do u plug in the numbersEDIT: oooo i get since at 3 sec its at a stand still its 0 but how do you do the 2.25 one?
 
Last edited:

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