Integral of sin(n*pi*x/L)cos(m*pi*x/L): Is n=m a Requirement?

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SUMMARY

The integral of sin(n*pi*x/L) * cos(m*pi*x/L) over the interval from 0 to L evaluates to zero unless n equals m. This conclusion is supported by the application of trigonometric identities, specifically the product-to-sum identities, which simplify the expression. When n and m are equal, the integral yields a non-zero result, confirming that the condition n=m is indeed a requirement for a non-zero integral.

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chota
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if i have to find the integral of

sin(n*pi*x/L) * cos(m*pi*x/L) between 0<=x<=L

is it true that this integral will be 0 every where except where n=m?

please and thank you.
 
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Is there a trig identity that will simplify this for us a little bit?

sin(u)cos(v)=\frac{1}{2}\left[sin(u+v)+sin(u-v)\right]

With this trig identity, do you suppose that the integral will be equal to zero when n is not equal to m? When n is equal to m?
 

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