Integrals By Parts With Infinity As Limit

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Discussion Overview

The discussion revolves around the evaluation of the improper integral \(\int_0^\infty \lambda x e^{-\lambda x} dx\) using integration by parts. Participants explore the application of limits at infinity and zero in the context of this integral, discussing both the mathematical process and the underlying concepts related to exponential distributions.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant asks how to handle the limits after applying integration by parts.
  • Another participant suggests that for \(\lambda > 0\), polynomials dominate at \(x = 0\) while exponentials dominate at infinity.
  • A different participant emphasizes the need to express the improper integral as a limit of a proper integral, providing a specific formulation involving \(b\) approaching infinity.
  • One participant claims that the integral represents the first moment of an exponential distribution, asserting it equals \(\lambda^{-1}\) without further evaluation.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of evaluating the integral, with some focusing on the limits and others asserting the result based on the properties of the exponential distribution. No consensus is reached regarding the evaluation process.

Contextual Notes

The discussion includes assumptions about the behavior of functions at the limits and the interpretation of the integral in terms of probability distributions. There are unresolved steps regarding the evaluation of the antiderivative and the application of limits.

kloong
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\int_0^\infty \lambda x e^{-\lambda x} dx

How do I use the limits (infinity and 0) after getting the equation from integration by parts?
 
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Just do the limits. Remember, if lambda > 0, polynomials dominate at x = 0, and exponentials dominate at infinity.
 
You need to write your improper integral as the limit of a proper integral.
\int_0^\infty \lambda x e^{-\lambda x} dx = \lim_{b \to \infty} \int_0^b \lambda x e^{-\lambda x} dx

After you get your antiderivative, evaluate it at b and 0, and take the limit as b --> infinity.
 
No need to evaluate it. The integral is the first moment (mean) of an exponential distribution on x, so it is equal to \lambda^{-1}
 

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