Integrating a Vector Field Over a Circular Disk

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To integrate the vector field over a circular disk, the integral involves the expression for the velocity field, which combines translational and rotational components. The integration is performed over the area of the disk defined by radius R, with the position vector \(\vec{r}\) originating from the center. Both the translational velocity \(\vec{v}\) and the angular velocity \(\vec{\omega}\) are treated as constants throughout the integration. It is important to note that \(\vec{\omega}\) is assumed to be perpendicular to the disk. A step-by-step approach is necessary to clarify the integration process and the origin of the integral.
Phizyk
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Hi,
How do integrate this? I wish to see it step by step and I'm glad for any help i can get.
\int_{ \vec{r}\in{A}} \frac{ \vec{v}+ \vec{\omega}\times\vec{r}}{| \vec{v}+ \vec{\omega}\times\vec{r}|}d^{2}r
where A is area of disk with radius R.
 
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Can you explain some details? Where does the integral come from? Are v and omega constant for all r? Is omega perpendicular to the disk?
 
\omega is the angular velocity of the disk, v is the translational velocity. v and \omega are constants. Integration extends over the area of the disk with \vec{r} vectors starting at the center.
 
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