Integrating sin(u) + u⁶

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jaychay
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Integral of (sin(sin(x)) + sin^6(x)) cos(x) dx, typeset as an equation.


Can you please help me ?
I have tried to do it many times but still got the wrong answer.
Thank you in advance.
 
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Make the substitution $t = \sin x$.
 
Opalg said:
Make the substitution $t = \sin x$.
Handwritten substitution work: u = sin x, du = cos x, then the integral of sin(u + u^6) cos x dx rewritten with cos x cancelled, leaving the integral of sin(u + u^6) du.
I am stuck here
Can you please help me ?
 
Get the parentheses in the right place! It's not $\sin(u+u^6)$, but $\sin(u) + u^6$, which is much easier to integrate.
 
Opalg said:
Get the parentheses in the right place! It's not $\sin(u+u^6)$, but $\sin(u) + u^6$, which is much easier to integrate.
Thank you very much
I understand now