Integrating x^(1/3)

[butoyzki]

HELP, URGENT! how do i integrate (x)^1/3

how do i solve this?
please help me integrate (X)^1/3

 

[okevino]

x^(-2/3) / 3

aka..
1 over 3x^(2/3)

 

[mezarashi]

The same way you would integrate X^1.

If I were to write X^1 as X^(3/3), would this help you see the similarity? How would you integrate X^(3/3)?

 

[VietDao29]

x^(-2/3) / 3

aka..
1 over 3x^(2/3)

Errr, well, it's integration, not differentiation.

For all $$\alpha \in \mathbb{R}$$, not -1. We have:
$$\int x ^ {\alpha} dx = \frac{x ^ {\alpha + 1}}{\alpha + 1} + C$$

:)

 

[okevino]

opps..
then it's

3x^(4/3) over 4