Intensity of Near-Infrared Spectroscopy Laser

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Homework Help Overview

The discussion revolves around the application of the Beer-Lambert law in the context of near-infrared spectroscopy (NIRS) used for noninvasive brain imaging. Participants are tasked with calculating the intensity of a laser beam after it penetrates human tissue and determining the electric field of the initial light beam.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to calculate the initial intensity of the laser beam using the power and cross-sectional area, questioning whether the area calculation is correct due to confusion over diameter versus radius. There is also discussion about unit conversions and their impact on the results.

Discussion Status

Some participants have identified potential errors in calculations and unit conversions, leading to discrepancies in the results. There is ongoing clarification regarding the correct interpretation of the given values and the equations to use, but no consensus has been reached on the correct approach yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the type of guidance they can receive. There is a focus on ensuring that calculations adhere to the correct units and interpretations of the physical quantities involved.

creative_wind
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Homework Statement



Light in the near-infrared (close to visible red) can penetrate surprisingly far through human tissue, a fact that is being used to "illuminate" the interior of the brain in a noninvasve technique known as near-infrared spectroscopy (NIRS). In this procedure an optical fiber carrying a beam of infrared laser light with a power of 1.5 mW and a cross-sectional diameter of 1.4 mm is placed against the skull. Some of the light enters the brain, where it scatters from hemoglobin in the blood. The scattered light is picked up by a detector and analyzed by a computer.

(a) According to the Beer-Lambert law, the intensity of light, I, decreases with penedtration distance, d, as I=I0e-µd, where I0 is the initial intensity of the beam and µ = 4.7 cm-1 for a typical case. Find the intensity of the laser beam after it penetrates through 3.5 cm of tissue.

Answer should be in mW/m2

(b) Find the electric field of the initial light beam.

Answer should be in kV/m


Homework Equations


I0=P/A
I=I0e-µd
I=c\epsilon0E2 (I think this is the equation I need to answer b)
\epsilon0=8.85*10-12

The Attempt at a Solution



a)
Step 1) Solve for I0 (I'm assuming the cross-sectional area refers to a circle)
I0=P/A = 1.5mW/(pi*(1.4*10-4m/2)2 = 9.744*105mW/m2

Step 2) Solve for I
I=I0e-µd = (9.744*105mW/m2)*e(-0.047m-1*0.035m) = 9.728*105mW/m2

This answer gets me "Your answer differs from the correct answer by orders of magnitude." Since the e term is about 0.998, my I0 must be incorrect. The math is correct (as far as me quadruple-checking can affirm :frown:) so is there a different equation I should be using to determine I0?
 
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creative_wind said:

Homework Statement



Light in the near-infrared (close to visible red) can penetrate surprisingly far through human tissue, a fact that is being used to "illuminate" the interior of the brain in a noninvasve technique known as near-infrared spectroscopy (NIRS). In this procedure an optical fiber carrying a beam of infrared laser light with a power of 1.5 mW and a cross-sectional diameter of 1.4 mm is placed against the skull. Some of the light enters the brain, where it scatters from hemoglobin in the blood. The scattered light is picked up by a detector and analyzed by a computer.

(a) According to the Beer-Lambert law, the intensity of light, I, decreases with penedtration distance, d, as I=I0e-µd, where I0 is the initial intensity of the beam and µ = 4.7 cm-1 for a typical case. Find the intensity of the laser beam after it penetrates through 3.5 cm of tissue.

Answer should be in mW/m2

(b) Find the electric field of the initial light beam.

Answer should be in kV/m

Homework Equations


I0=P/A
I=I0e-µd
I=c\epsilon0E2 (I think this is the equation I need to answer b)
\epsilon0=8.85*10-12

The Attempt at a Solution



a)
Step 1) Solve for I0 (I'm assuming the cross-sectional area refers to a circle)
I0=P/A = 1.5mW/(pi*(1.4*10-4m/2)2 = 9.744*105mW/m2

Step 2) Solve for I
I=I0e-µd = (9.744*105mW/m2)*e(-0.047m-1*0.035m) = 9.728*105mW/m2

This answer gets me "Your answer differs from the correct answer by orders of magnitude." Since the e term is about 0.998, my I0 must be incorrect. The math is correct (as far as me quadruple-checking can affirm :frown:) so is there a different equation I should be using to determine I0?

You made two mistakes, one small, one big:

First, you have been given the diameter of a circle, not the radius. That's a factor of 4 you miss.

Second, 1cm^-1 is certainly not equal to 0.01m^-1: this is where you're orders of magnitude off.
 
The 1.4e-4 was a typing error on my part, it should have been -3, which still yields the initial value for I that I wrote. I did completely err on the m^-1 though. Thank you so much for that!

As for part b, I solved for E using the correct I value of 9.744e11 W/m^2.
E=(I/c*constant)^1/2
E=(9.744e11/3e8*8.85e-12)^1/2=1.92e7 V/m=1.92e4 kV/m which is off by orders of magnitude again. BAH! Your help is greatly appreciated.
 
Where are you getting 9.744e11 from? Your intensity is orders of magnitude off, which is the problem here.
 
It's from my calculation in the first post for I0. It's in megawatts, I converted it to watts for the second step so I wouldn't have unit problems.

(9.744*105mW/m2)*(1*106/1mW)=9.744*1011.

I used this number to calculate the answer for a) which was correct. Please tell me how it's orders of magnitude off for part b).
 
"mW" is milliwatts. Megawatts would be "MW".
 
Forgive my lack of shift-usage. Can you help me answer the problem at all?
 
It's supposed to be milliwatts (mW), as written originally. Nobody is going to shoot a megawatt laser through somebody's head in a noninvasive technique, since a megawatt would be quite invasive, to put it mildly.

Just do the conversion from mW to W.
 

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